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bba48b311f
left side of assignments can now be various different things instead of just variables. any statement that returns a reference can be used to assign to the value behind that reference. variables are automatically referenced, so the '&' can be omitted. if the variable contains a reference and that reference should be used, dereference it with *varname instead of just varname.
38 lines
1.6 KiB
Plaintext
Executable File
38 lines
1.6 KiB
Plaintext
Executable File
// this is true by default so the example doesn't finish too quickly or too slowly depending on your hardware.
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// you can set it to false and tweak the max value for a more authentic cpu-heavy workload.
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fake_delay = true
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// this will be shared between the two threads to report the progress in percent (0-100%).
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progress = 0
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// an anonymous function that sums all numbers from 0 to max.
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// it captures the progress variable and uses it to report its status to the main thread, which will periodically print the current progress.
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// once done, it returns a string with the sum of all numbers.
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calculator = (max int) {
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sum = 0
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for i max {
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i = i + 1
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// println("i: {0}".format(i.to_string()))
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println("i: {0} s: {1}".format(i.to_string() sum.to_string()))
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sum = sum + i + 1
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if fake_delay sleep(1)
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v = i * 100 / max
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}
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"the sum of all numbers from 0 to {0} is {1}!".format(max.to_string() sum.to_string())
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}
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// start the thread. if fake_delay is true, calculate 1+2+3+4+5+6+7+8+9+10. if fake_delay is false, count up to some ridiculously large number.
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slow_calculation_thread = calculator.thread(if fake_delay 10 else 20000000)
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// every second, print the progress. once it reaches 100%, stop
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loop {
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sleep(1)
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println("{0}%".format(progress.to_string()))
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progress == 100 // break from the loop
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}
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// use await() to get the result from the thread. if the thread is still running, this will block until the thread finishes.
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result = slow_calculation_thread.await()
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println("Thread finished, result: {0}".format(result))
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